Cubs 100-1 win the NL Central?

BigHurt007 · Sep 8, 2015

If they can somehow beat Wacha they will be 5.5 back with plenty to go, and one more game tomorrow
Watching the Cards on Sunday vs Pirates was a snooze. Now the Cubs are manhandling them at their beloved Busch?
I see the Cards wrap this season up with a lot of games vs Reds/Brewers. I don't follow the NL that closely, but these two don't seem to be very good. Then again, the Cubs play these teams too
When are Adams and Holliday coming back? Seems like they shoulda been back already, no?

Yes it's a longshot. But I was surprised to see 100-1

razorbackpicks · Sep 8, 2015

BigHurt007 said:
If they can somehow beat Wacha they will be 5.5 back with plenty to go, and one more game tomorrow
Watching the Cards on Sunday vs Pirates was a snooze. Now the Cubs are manhandling them at their beloved Busch?
I see the Cards wrap this season up with a lot of games vs Reds/Brewers. I don't follow the NL that closely, but these two don't seem to be very good. Then again, the Cubs play these teams too
When are Adams and Holliday coming back? Seems like they shoulda been back already, no?

Yes it's a longshot. But I was surprised to see 100-1

I am guessing it's 100-1 because they would ahve to jump both the Cards and Pirates. And i believe they still have another series agains the cards and 2 more against the Pirates?

Mosi · Sep 8, 2015

I was breaking down the exact same things yesterday and debating it with my Cardinal friend who said it was impossible. It is possible, however with the schedules and the Pirates it is a longshot. I don't know let's call it a 100-1 longshot (insert sarcastic smiley face here).

I am going to dig deeper into this, hopefully before the game goes this evening. Come on, $100 to win $10K is a bit enticing.

Good luck with whatever you choose BH007. Cheers!

BigHurt007 · Sep 8, 2015

Thanks for the reply, glad to see someone else has looked at this.
Tonight is a tough task. Tomorrow is winnable
I put $20 on it. Really don't see this as being impossible.