What is the formula for......

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What is the formula for figuring out how many round robin parlays you get out of a certain amount of teams. Such as how many different combinations are there if you take 12 teams and you want to have four team round robins?
 

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If you want to make X team parlays out of Y selections, the formula is....

Y!/(X!*(Y-X)!)

where A! = A*(A-1)*(A-2)*...*2*1

eg. using 12 selections in 4 team parlays...

12!/(4!*(12-4)!) = 12!/(4!*8!) = 12*11*10*9/(4*3*2) = 11*5*9 = 495 four team parlays
 

Rx God
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123: If you must parlay, reduce number of teams, stick to 3-teamers, you'll be better off... lose less. At 4-teams is when the book reams you hardest vs. 3 teams.

The reasons not to RR a parlay are enormous. A 2 -teamer is fine with corelation, a 3-teamer is fine with great odds, little need to go past that !
 

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The number of teams, times the number of teams minus one, all divided by two
 
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Thank you guys. Not thinking about really doing it myself. I had a friend who thought there was a sure fire way to make money betting parlays. I told him he was wrong but I did not have the facts for him.
 

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