Figuring out Bookmaker take-out %

I m trying to learn how to figure out take-out percentages for various wagers...Have a look at the following conclusion and please correct mistakes.

Example A)

California Golden Seals -6 -110 hypothetical football game
Winnipeg Jets +6 -110

-110 coverted to decimal form is 1.91
1.91 convert to % is 52.36%

52.36 * 2(# of subjects) = 104.72 %

Does this mean that the probability of a PUSH is 4.72 % or the take-out or hold is 4.72 % ??????



Example B) In Canada we have sports lottery, below is an example of a typical line.......


Vancouver Grizzlies 2.10 ( a win is considered by 6 pts or more
TIE 3.00 ( a tie is considered 5 pts or less)
Harlem Globetrotters 2.40 realistically - 5.5


So here goes:

2.10 ==== 47.62 % chance of winning
3.00 =====33.33 %
2.40=====41.67 %

Added % = 122.62 So once again is this 22.62 % the takeout percentage??

Is this correct???Thanks very much for your replies....

PRJ

Almost correct. You have divide 100 with 122.62

100/122.62=0.816, so every dollar bookmaker gives back 81.6 cents

And then bookmakers holding 1-0.816=18.4%

Faceless said:

Almost correct. You have divide 100 with 122.62

100/122.62=0.816, so every dollar bookmaker gives back 81.6 cents

And then bookmakers holding 1-0.816=18.4%

Click to expand...

there is an old thread at sharpsportsbetting with a discussion of this

http://www.sharpsportsbetting.com/forums/free/general/index.cgi/read/12453#Responses