The juice can really be deadly.

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Was thinking a bit after I read some of the responses to my nba thread.

The juice can really be deadly. Most lines are what 10 percent juice? So even if you win 60 percent of your bets the best you can do is break even. You will be up only 7 percent if you are one of the great cappers and can hit 67 percent of your bets.

This leads me to beleive that you can only win by doing one of two things.

1. Increase your wagering amounts on games that you feel are the most favorable.

or

2. Win over 60 percent of your wagers. (Very difficult)
 

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why do u need to hit 60% to break even on -110 juice?
 

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Because -110 is 10 percent juice, meaning if you hit 50 percent of your bets you would actually only be getting 40 percent in return.
 

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BaseballGuy said:
Because -110 is 10 percent juice, meaning if you hit 50 percent of your bets you would actually only be getting 40 percent in return.
what if i hit 53% baseball guy?
 

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BaseballGuy said:
Then you will still be down 7 percent because you paid 10 percent in juice.
if i am wrong here please people tell me, but i dont get it!

wager 100 games at -110

win 53 = +5300
lose 47 = -5170

Result = +130
 

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Ok take this example.

You make 4 wagers.


BET A -110 $1000 To win $900 -WIN
BET B -110 $1000 To win $900 -WIN
BET C -110 $1000 To win $900 -LOSS
BET D -110 $1000 To win $900 -LOSS

So you started with 4000.00

2 of your bets won and two of your bets lost, giving you $3800.00 total. So even though you hit 50 percent of your wagers you still lost $200.00
 

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BaseballGuy said:
Ok take this example.

You make 4 wagers.


BET A -110 $1000 To win $900 -WIN
BET B -110 $1000 To win $900 -WIN
BET C -110 $1000 To win $900 -LOSS
BET D -110 $1000 To win $900 -LOSS

So you started with 4000.00

2 of your bets won and two of your bets lost, giving you $3800.00 total. So even though you hit 50 percent of your wagers you still lost $200.00
huh? i didnt say 50%....i said 53%!!!!!!
isnt this sports wagering 101?
 

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please go back and look at my example and tell me where i am wrong?
 

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BaseballGuy said:
Ok take this example.

You make 4 wagers.


BET A -110 $1000 To win $900 -WIN
BET B -110 $1000 To win $900 -WIN
BET C -110 $1000 To win $900 -LOSS
BET D -110 $1000 To win $900 -LOSS

So you started with 4000.00

2 of your bets won and two of your bets lost, giving you $3800.00 total. So even though you hit 50 percent of your wagers you still lost $200.00
besides it would be 990 to win 900
 

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if i am wrong here please people tell me, but i dont get it!

wager 100 games at -110

win 53 = +5300
lose 47 = -5170

Result = +130<!-- / message -->

It would all depend on how you bet it..

If you risk 110 to win 100 it would be different than if you risked 100 to win 90 factoring in the juice.
 

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BaseballGuy said:
It would all depend on how you bet it..

If you risk 110 to win 100 it would be different than if you risked 100 to win 90 factoring in the juice.
Baseball Guy...slow down...a -110 it would NEVER be 100 to win 90!
 

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LMAO,


baseball guy... anyone who knows anything about gamblin knows you have to hit 52.5% of your bets laying -110 over the long term to break even....


DO NOT TRY TO ARGUE IT.... IT IS A FACT....
 

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BaseballGuy said:
No.. It's 1000 to win 900 @ -110
Baseball Guy....please go to your nearest calculator......to win $900 at -110 you lay $990.....
 

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sherman said:
Baseball Guy....please go to your nearest calculator......to win $900 at -110 you lay $990.....
I was using figures of 1000.

Does not matter how you slice it.. You still lose money if you hit 50 percent of your bets.
 

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SportSavant said:
LMAO,


baseball guy... anyone who knows anything about gamblin knows you have to hit 52.5% of your bets laying -110 over the long term to break even....


DO NOT TRY TO ARGUE IT.... IT IS A FACT....
Whose arguing?
 

It's like sum fucking Beckett play that we're rehe
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need to hit 52.3857% to break even

assumes full 10% juice, no bonus, no transaction fees
 

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