Round Robin Reverse Question

Labeeb · Sep 8, 2005

Assuming you have three teams, A,B,C, would it be:

a,b
a,c
b,c

Or would it be like a box yielding 6 combinations?

Thanks in advance.

cincy_ · Sep 8, 2005

Labeeb said:
Assuming you have three teams, A,B,C, would it be:

a,b
a,c
b,c

Or would it be like a box yielding 6 combinations?

Thanks in advance.

NEVER have done a RR Reverse but if it a RR and a Reverse Action combined, you're making IF-BETS and not parlays, so you would have 6 boxes, I would THINK.

wilheim · Sep 8, 2005

Three Team Round Robin Reverse Play Team A in Game 1, Play Team B in Game 2 and Play Team C in Game 3...

A 3 Play Reverse has 6 different 2team combinations:

1) If A wins then B;
2) If A wins then C;
3) If B wins then A;
4) If B wins then C;
5) If C wins then A;
6) If C wins then B.

Bet $100 a way if you hit all three you win $1200
win two and lose one win $160
Lose two Lose $460
Lose three lose $660

Assuming all bets are minus $110.

wil.

JudgeWapner · Sep 8, 2005

Wil is correct as always.

wilheim · Sep 8, 2005

Thanks Judge - Pura Vida....

BTW - "You can't eat the orange and throw the peel away - a man is not a piece of fruit!" ..

wil.:toast:

Labeeb · Sep 8, 2005

I guess I should have said it would yield three different REVERSES:

a,b
a,c
b,c

The way I worded it earlier it made it seem like I thought there were only 3 COMBINATIONS. With the usual rules of reverses applying. In looking at Wil's explanation, 3 REVERSES with a total of 6 COMBINATIONS would be the case here. Thanks guys.