What is the answer to this math problem?

SmokeyLa · Aug 18, 2007

(My neice needs help)

(6X3)3
_______
X15

The 3's and the 15 are supposed to by exponents, so its six X to the 3rd, to the 3rd, over x to the 15th

I guessed 2x over X to the 5th but I think its wrong

Thanks

oldmanTED · Aug 18, 2007

X to the 15th power equals 10,077,696.

6 to the 3rd power and the sum to the 3rd power is 10,077,696.

blueedwards · Aug 18, 2007

2 pie r

oldmanTED · Aug 18, 2007

blue edwards said:
2 pie r

Believe that is the circumference of a circle.

levistep · Aug 18, 2007

216x^-5

Don't have my calculator on me, but that's my guess.

blueedwards · Aug 18, 2007

oldmanTED said:
Believe that is the circumference of a circle.

dont back-talk me teddy

PornoPaul · Aug 18, 2007

:monsters- 4

DonMelchor · Aug 18, 2007

B, always B

levistep · Aug 18, 2007

levistep said:
216x^-5

Don't have my calculator on me, but that's my guess.

I think this is the proper form, if my guess is correct.

1 / (216X^6)

oldmanTED · Aug 18, 2007

Misread the equation.

Answer should be (6X3) over (X5). Then find X.

dave11486 · Aug 18, 2007

I have 216/x^9

I took 6^3 = 216

(x^3)^3 which is just like adding 3+3 giving me x^6

So, now we have 216x^6/x^15, then its just like subtraction (x^6 - x^15 = x^9)

Final answer is 216/x^9

I think this is right. Anyone?

dave11486 · Aug 18, 2007

Sorry the answer is, in fact, 216/x^6.

Go to quickmath.com to confirm if you would like.

I clearly was suppose to multiply there where I just added.

levistep · Aug 18, 2007

My bad, that is right.

oldmanTED · Aug 18, 2007

dave11486 said:
Sorry the answer is, in fact, 216/x^6.

Go to quickmath.com to confirm if you would like.

I clearly was suppose to multiply there where I just added.

The equation is not 6 to the third power. X is to the third power. I made that mistake at first.

The numerator is (6 times X to the third power) with that sum all times the third power.
The denominator is X to the 15th power. The equation calls for finding the value of X, not another equation.

doubledeuce22 · Aug 18, 2007

Laurent Robinson.

dave11486 · Aug 18, 2007

I am very confused, all I did was simplify what was put in front of me. I doesn't say solve for X, but if that is the case so be it.

It has (6x^3)^3/x^15, no?

That is what I am reading.

oldmanTED · Aug 18, 2007

dave11486 said:
I am very confused, all I did was simplify what was put in front of me. I doesn't say solve for X, but if that is the case so be it.

It has (6x^3)^3/x^15, no?

That is what I am reading.

That is a correct reading of the equation. Note that X is to the third and fifteenth power. You took 6 to the third power to get 216. I originally did the same as I misread the author's equation.

I believe the first step yields (6x^3)/x^5

dave11486 · Aug 18, 2007

But that is what you do. Hence the parentheses. I mean I guess I just need to understand what you are doing.

oldmanTED · Aug 18, 2007

dave11486 said:
But that is what you do. Hence the parentheses. I mean I guess I just need to understand what you are doing.

I am trying to find the value of X. The first step I believe is dividing the denominator exponent by the numerator exponent which leaves you with (6x^3)/x^5. Was a math major but unfortunately that was 40 years ago and my memory is not as sharp as when I was younger.

cdsmoney · Aug 18, 2007

Will side with Dave on this one. As I remember the general rules indicate solving everything in parantheses before moving on the the equation.

6(x^3)^3 = 6x^9 is definitely different from (6x^3)^3 = 216x^9.

Dave, I think the 'addition' rule you are thinking of is one of the form (X^3)*(X^3) = X^6.

OMT, out of curiousity, in an earlier post you arrived at a value for X. What value were you using to solve for X?

Have to love a sports forum where we can talk math at 12:00 a.m. on a Saturday night (not sure if this mean I need a life LoL).