Just seeing if anyone here can solve this pretty simple math problem...

JakeT. · Feb 22, 2008

Long story short, even though I've taken much higher level math classes, I got sent back to the 2nd part of Algebra because I've taken so much time off and it's a good refresher. Anyway...

One canned juice drink is 15% orange juice; another is 5% orange juice. How many liters of each should be mixed together in order to get 10L that is 11% orange juice?

Only reason I asked is because even though it's pretty easy once I figured it out, it really made me think back and it stumped the hell out of me for a few minutes. Didn't realize how much I've forgotten about math.

InsideThePylons · Feb 22, 2008

6 and 4

JakeT. · Feb 22, 2008

Inside The Pylons said:
6 and 4

Nice work stud. :103631605

quantumleap · Feb 22, 2008

If you need to put something down on paper try this-

Your looking for 1.10 Liters of total OJ since 11% of 10 Liters is 1.10 Liters.

So say the amount in volume of the first drink is X Liters and the amount in volume of the second drink is Y Liters. To figure out how much was needed of each would give us this equation:

0.15X + 0.05Y = 1.1

Also, the total amount of liquid can be represented as:

X + Y = 10

Solving for Y would give us:

Y = 10 - X

Now if we substitute this formula in for Y in the first equation we get:
0.15X + 0.05(10 - X) = 1.1
0.15X + 0.50 - 0.05X = 1.1
0.10X + 0.50 = 1.1
0.10X = 0.60
X = 6

Substituting in the second formula we get:
6 + Y = 10
Y = 4

ProPokerPlayer · Feb 22, 2008

How many people need to be in a room before there is a 50/50 chance that 2 of them share the same birthday ????

quantumleap · Feb 22, 2008

ProPokerPlayer said:
How many people need to be in a room before there is a 50/50 chance that 2 of them share the same birthday ????

23.

http://en.wikipedia.org/wiki/Birthday_paradox

InsideThePylons · Feb 22, 2008

I'll take Under every time.

Birth dates are not equally distributed.

Certain months have more than others.

fhmesq44 · Feb 22, 2008

quantumleap said:
23.

http://en.wikipedia.org/wiki/Birthday_paradox

That is bull shit

quantumleap · Feb 22, 2008

fhmesq44 said:
That is bull shit

Then refute it using logic.

Not saying you are wrong. Just saying prove that it is what you say it is.

quantumleap · Feb 22, 2008

Inside The Pylons said:
I'll take Under every time.

Birth dates are not equally distributed.

Certain months have more than others.

Good point. The article states that this is an approximation and is explained this way:

"In particular, many children are born in the summer, especially the months of August and September (for the northern hemisphere) [1], and in the U.S. it has been noted that many children are conceived around the holidays of Christmas and New Year's Day; and, in environments like classrooms where many people share a birth year, it becomes relevant that due to the way hospitals work, where C-sections and induced labor are not generally scheduled on the weekend, more children are born on Mondays and Tuesdays than on weekends. Both of these factors tend to increase the chance of identical birth dates, since a denser subset has more possible pairs (in the extreme case when everyone was born on three days, there would obviously be many identical birthdays). The birthday problem for such non-constant birthday probabilities was tackled by Murray Klamkin in 1967. A formal proof that the probability of two matching birthdays is least for a uniform distribution of birthdays was given by D. Bloom (1973)

stolidog · Feb 22, 2008

Quantum- your ability to solve math problems quickly always amazes me. And I had a minor in mathematics in college.

djmatt · Feb 22, 2008

anyone ever read Freakonomics??

quantumleap · Feb 22, 2008

stolidog said:
Quantum- your ability to solve math problems quickly always amazes me. And I had a minor in mathematics in college.

Thanks stoli.

%^_

VIEJODINOSAUR · Feb 22, 2008

quantumleap said:
Thanks stoli.

%^_

That's why I hung out with him down here in Costa Rica...raises my IQ a whole lot...he is one smart son of a bitch...QL, impressed with that birthday equation, but how many rum and cokes can I consume until I become legally wasted?

GreenDoberman · Feb 22, 2008

Here's one for QL and VD:

If a certain American walks in the Del Rey with $500 in his wallet and at the same time a prostitute dressed in a school girl outfit walks in, how much does the American have in his wallet an hour later?

Bonus question:
If a drunk guy in a Hawaii jersey is sitting at the Del Rey and a Dominican girl walks by his table, estimate the percentage chances that drunk guy is still sitting at the table fifteen minutes later.

fhmesq44 · Feb 22, 2008

quantumleap said:
Then refute it using logic.

Not saying you are wrong. Just saying prove that it is what you say it is.

I understand the math and mathematically speaking it is accurate, my response was more intuitive than anything else.

VIEJODINOSAUR · Feb 22, 2008

The girl in the plaid dress is automatically a lottery winner for 500 and then will have the guy at the cash machine an hour later maxing out his credit cards..he will be on the next plane to Denver the next day...

The guy with the Hawaiian shirt has no chance of lasting 15 minutes...more like 5...

quantumleap · Feb 22, 2008

GreenDoberman said:
Here's one for QL and VD:

If a certain American walks in the Del Rey with $500 in his wallet and at the same time a prostitute dressed in a school girl outfit walks in, how much does the American have in his wallet an hour later?

Bonus question:
If a drunk guy in a Hawaii jersey is sitting at the Del Rey and a Dominican girl walks by his table, estimate the percentage chances that drunk guy is still sitting at the table fifteen minutes later.

You got me stumped with that one GD.

:think2:

:nohead:

quantumleap · Feb 22, 2008

VIEJO DINOSAUR said:
That's why I hung out with him down here in Costa Rica...raises my IQ a whole lot...he is one smart son of a bitch...QL, impressed with that birthday equation, but how many rum and cokes can I consume until I become legally wasted?

Thanks VD.

Does the answer have something to do with "the angle of the dangle..."?

VIEJODINOSAUR · Feb 22, 2008

quantumleap said:
Thanks VD.

Does the answer have something to do with "the angle of the dangle..."?

You are for sure the smartest guy I know..when you, GD, and TTinCo were down here, all we needed was Woof Daddy to be here and we would have been rich and smart...too much for those girls to handle...

Just seeing if anyone here can solve this pretty simple math problem...

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