parlay combinations

AdamD7

New member

Joined

May 14, 2009

Messages

9

Tokens

• May 20, 2009

• #1

If you had 20 teams squaring off against each other and covered every possible combination with parlays, how many combinations would be in that 10 team parlay ? Just out of curiousity.......

Anyone know how to figure that one out?

 

AdamD7

New member

Joined

May 14, 2009

Messages

9

Tokens

• May 20, 2009

• #2

......and this is just for knowledge only. I'm not gonna actually try to place a bet on on combinations for like $10,000 or anything!

It's pretty much to settle an argument at work, but none of us are smart enough to figure out the math on this.

 

geeze

New member

Joined

Sep 21, 2004

Messages

1,362

Tokens

• May 23, 2009

• #3

10x9 = 90

1X2= 2

90 divided by 2 = 45 combinations.

 

dgr81

New member

Joined

Sep 22, 2006

Messages

740

Tokens

• May 23, 2009

• #4

2^10=1024

1024 combinations

 

SpreadOffense

New member

Joined

Jan 18, 2009

Messages

223

Tokens

• May 23, 2009

• #5

lol, if there were only 45 combinations for a 10 team parlay, everyone would be rich.

there's actually 1024 different combinations with a .00098 chance of winning

 

geeze

New member

Joined

Sep 21, 2004

Messages

1,362

Tokens

• May 23, 2009

• #6

he didn't ask about one 10 teamer.

He asked how many TWO teamers.

45.

 

Wellwood

Ice Cold

Joined

Nov 25, 2008

Messages

485

Tokens

• May 23, 2009

• #7

geeze said:

he didn't ask about one 10 teamer.

He asked how many TWO teamers.

45.

Click to expand...

No, he asked about one 10 teamer.

AdamD7 said:

how many combinations would be in that 10 team parlay ?

Click to expand...

 

geeze

New member

Joined

Sep 21, 2004

Messages

1,362

Tokens

• May 23, 2009

• #8

Guess I gave him the correct information for a question he did not ask.
Here's some more he might find useful.

45 two-team parlays in 10 games.


120 three team parlays in 10 games.


210 four-team parlays in 10 games.