Ok RX Math guys ...... Texas banker offers $1 million for solution to insane math problem

Search
Joined
Jan 17, 2007
Messages
99,709
Tokens
Texas banker offers $1 million for solution to insane math problem


The Beal Prize previously held a value of $100, 000.



math1.jpg
Photo credit: Flickr

<tbody>
</tbody>

Science Recorder | Ellen Miller | Thursday, June 06, 2013
<ins style="display:inline-table;border:none;height:250px;margin:0;padding:0;position:relative;visibility:visible;width:300px"><ins id="aswift_0_anchor" style="display:block;border:none;height:250px;margin:0;padding:0;position:relative;visibility:visible;width:300px"></ins></ins>
<ins style="display:inline-table;border:none;height:250px;margin:0;padding:0;position:relative;visibility:visible;width:300px"></ins>

<tbody>
</tbody>
Banker Andrew Beal, a mathematics enthusiast, has increased the prize money to $1 million to solve a mathematical equation that has puzzled mathematicians for decades. The prize money, held in trust by the American Mathematical Society, will be awarded to the mathematician who publishes a proof for or counterexample of the conjecture.


The Beal conjecture states that if A[SUP]x[/SUP] + B[SUP]y[/SUP] = C[SUP]z[/SUP] , where A, B, C, x, y and z are positive integers and are all greater than 2, then A, B and C must have a common prime factor.


In a news release announcing the increased prize money, the AMS explains, “By way of example, 3[SUP]3[/SUP] + 6[SUP]3[/SUP] = 3[SUP]5[/SUP], but the numbers that are the bases have a common factor of 3, so the equation does not disprove the theorem; it is not a counterexample.”


The Beal conjecture implies Fermat’s Last Theorem, another number theory that was easy to state but difficult to prove. Three hundred years ago, Pierre de Fermat claimed to have proof but did not leave a record, and it took until the 1980s for proof to be discovered.


Beal founded the prize in 1997 to inspire young people to invest in the world of mathematics. He was inspired by the prize that was offered for proving Fermat’s Last Theorem and hopes that increasing the prize will draw more attention to mathematics and more excitement from young people.


It is a tough road for those hoping to prove or disprove the conjecture. Mathematicians must first have their proof or counterexample published in a respected mathematical journal. They can then notify the American Mathematical Society of their article, but must wait a period of two years during which time their solution must be widely accepted by the mathematical community. After that, the committee will decide whether the solution merits evaluation.

Deliberations are confidential, and the committee will decide on whether to award the prize or pause deliberations if no clear answer can be given.


Prizes for solving difficult math problems are not new. In addition to the prize for Fermat’s Last Theorem, in 2000 the Clay Mathematics Institute created seven $1 million prizes for the “Millennium Problems.” One, the Poincaré Conjecture, has since been solved, though the mathematician Grigori Perelman turned down the prize money. The proof of Fermat’s Last Theorem was over 100 pages long and took Andrew Wiles seven years to solve; a solution for the Beal conjecture could easily surpass that length.


The Beal Prize previously held a value of $100, 000.


Read more: http://www.sciencerecorder.com/news...olution-to-insane-math-problem/#ixzz2VRl3zsjW
 

Member
Handicapper
Joined
Jan 16, 2010
Messages
17,864
Tokens
Thanks for giving me something to do today! However, two years from now, I will NOT be turning down the prize money...
 

Member
Joined
Sep 20, 2004
Messages
2,334
Tokens
Assume we are given an irreducible element
n
. An almost
everywhere extrinsic equation is a
subgroup
if it is composite, irreducible,
extrinsic and extrinsic.
In [8, 14], it is shown that the Riemann hypothesis holds. A central problem
in universal group theory is the description of random variables. Therefore
in this context, the results of [20] are highly relevant. In contrast, in future
work, we plan to address questions of associativity as well as existence. Here,
ellipticity is trivially a concern. Therefore recent developments in K-theory [35]
have raised the question of whether
h
U
is bounded by
^
Z
. Now here, splitting is
trivially a concern
 

Member
Handicapper
Joined
Oct 31, 2004
Messages
44,310
Tokens
I know the answer but im holding out for 2 million.
 

Conservatives, Patriots & Huskies return to glory
Handicapper
Joined
Sep 9, 2005
Messages
85,766
Tokens
I got a headache just reading the problem

what do they want again?
 

Breaking Bad Snob
Joined
Dec 5, 2004
Messages
13,430
Tokens
My mathematical prowess is well documented in this forum. Give me about 20 minutes.
 

Forum statistics

Threads
1,108,706
Messages
13,453,618
Members
99,429
Latest member
AnthonyPoi
The RX is the sports betting industry's leading information portal for bonuses, picks, and sportsbook reviews. Find the best deals offered by a sportsbook in your state and browse our free picks section.FacebookTwitterInstagramContact Usforum@therx.com